The problem in the image asks for the value of $x$ when:

$x = 2 \log_5 1 + \log_3 81$

Let's break it down step by step.

Step 1: Simplify the expression $\log_5 1$

The logarithm of 1 in any base is 0, so: $\log_5 1 = 0$

Thus, the first term becomes: $2 \times \log_5 1 = 2 \times 0 = 0$

Step 2: Simplify $\log_3 81$

We need to express 81 as a power of 3. Since $81 = 3^4$, we have: $\log_3 81 = \log_3 3^4 = 4$

Step 3: Combine the results

The equation now simplifies to: $x = 0 + 4 = 4$

Therefore, the value of $x$ is $\boxed{4}$.

Would you like more details or have any questions? Here are some related questions you might find interesting:

1. How do you evaluate logarithms with different bases?
2. What are the properties of logarithms that are useful in simplifying expressions?
3. How can you convert logarithms to a different base using the change of base formula?
4. What is the significance of logarithms in real-world applications?
5. How would you solve an equation involving a sum of logarithms with different bases?

Tip: Remember that the logarithm of 1 is always 0, regardless of the base, because any number raised to the power of 0 equals 1.