https://file.aiquickdraw.com/mathbot/file/17265383347338v94hab4.jpg

It looks like the image contains a system of linear equations solved using substitution. Let's go through the steps presented in the image and check the solution:

1. The system of equations is:
   \[
   x - 2y = 0
   \]
   \[
   2x - 5y = -4
   \]

2. **Substitution Method**:
   From the first equation, we can express \( x \) in terms of \( y \):
   \[
   x = 2y
   \]
   Substitute \( x = 2y \) into the second equation:
   \[
   2(2y) - 5y = -4
   \]
   Simplifying:
   \[
   4y - 5y = -4
   \]
   \[
   -y = -4
   \]
   \[
   y = 4
   \]

3. Now substitute \( y = 4 \) back into the first equation to find \( x \):
   \[
   x - 2(4) = 0
   \]
   \[
   x - 8 = 0
   \]
   \[
   x = 8
   \]

So, the solution to the system of equations is \( x = 8 \) and \( y = 4 \), corresponding to the point \( (8, 4) \).

The answer marked as **D** is correct based on this work.

Would you like more details on any part of this process?

Here are some related questions for practice:

1. Can you solve another system using substitution: \( 3x + 2y = 7 \) and \( x - y = 1 \)?
2. How would you solve a system using the elimination method instead of substitution?
3. Can you solve the system \( 4x - y = 10 \) and \( 2x + y = 6 \) using substitution?
4. What are the advantages and disadvantages of using substitution vs. elimination?
5. What happens if the system has no solution or infinitely many solutions?

**Tip**: When using substitution, it's often easiest to isolate the variable in the simplest equation first to reduce complexity later on.

Solve the system of equations using substitution.

Learn how to solve the system of linear equations x - 2y = 0 and 2x - 5y = -4 using the substitution method. This page provides a step-by-step walkthrough of the method, demonstrating how to isolate one variable, substitute it into the other equation, and solve for both variables. Suitable for high school students in Grades 9-12.

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