Let's solve the inequality:

\[
1(m - 6) + 16 \geq 7
\]

### Step-by-step solution:

1. **Distribute the 1**:
   Since multiplying by 1 doesn't change the expression, we can simply rewrite it:
   \[
   m - 6 + 16 \geq 7
   \]

2. **Combine like terms**:
   Simplify the constants \(-6 + 16\):
   \[
   m + 10 \geq 7
   \]

3. **Isolate \(m\)**:
   Subtract 10 from both sides to isolate \(m\):
   \[
   m \geq 7 - 10
   \]
   \[
   m \geq -3
   \]

### Final solution:
\[
m \geq -3
\]

Would you like more details, or do you have any questions?

Here are 5 related questions to expand on this topic:
1. How would the solution change if the inequality was strict (i.e., \( m - 6 + 16 > 7 \))?
2. Can you solve a similar inequality like \(2(m + 3) - 5 \leq 9\)?
3. How would you solve if you had a negative multiplier, such as \(-2(m - 4) \geq 6\)?
4. How do inequalities behave when dividing or multiplying by negative numbers?
5. What happens if you have a compound inequality like \(3 \leq m + 1 \leq 10\)?

**Tip:** Always remember to reverse the inequality sign when multiplying or dividing by a negative number!

Learn how to solve the linear inequality 1(m - 6) + 16 ≥ 7 step-by-step. This solution covers fundamental algebraic concepts, focusing on manipulating linear inequalities. Ideal for students in Grades 6-8.

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