Let's solve the inequality:

$1(m - 6) + 16 \geq 7$

Step-by-step solution:

1. Distribute the 1: Since multiplying by 1 doesn't change the expression, we can simply rewrite it: $m - 6 + 16 \geq 7$

2. Combine like terms: Simplify the constants $-6 + 16$: $m + 10 \geq 7$

3. Isolate $m$: Subtract 10 from both sides to isolate $m$: $m \geq 7 - 10$ $m \geq -3$

Final solution:

$m \geq -3$

Would you like more details, or do you have any questions?

Here are 5 related questions to expand on this topic:

1. How would the solution change if the inequality was strict (i.e., $m - 6 + 16 > 7$)?
2. Can you solve a similar inequality like $2(m + 3) - 5 \leq 9$?
3. How would you solve if you had a negative multiplier, such as $-2(m - 4) \geq 6$?
4. How do inequalities behave when dividing or multiplying by negative numbers?
5. What happens if you have a compound inequality like $3 \leq m + 1 \leq 10$?

Tip: Always remember to reverse the inequality sign when multiplying or dividing by a negative number!