To solve the inequality:

\[
-1 < 2x + 3
\]

### Step 1: Subtract 3 from both sides
\[
-1 - 3 < 2x
\]
\[
-4 < 2x
\]

### Step 2: Divide both sides by 2
\[
\frac{-4}{2} < x
\]
\[
-2 < x
\]

Thus, the solution is:
\[
x > -2
\]

The solution can also be written as:
\[
x \in (-2, \infty)
\]

Would you like more details on this, or do you have any other questions?

Here are 5 related questions you might consider:
1. How would you solve \( -2x + 5 \leq 1 \)?
2. What happens if the inequality has \( \geq \) or \( \leq \)?
3. Can inequalities have more than two terms? For example, \( 1 < 3x + 2 < 7 \)?
4. How do you solve a quadratic inequality like \( x^2 - 4x \leq 0 \)?
5. How would you graph the solution of \( -2 < x \)?

**Tip:** When dividing or multiplying an inequality by a negative number, remember to flip the inequality sign.

Solve the linear inequality -1 < 2x + 3 with a clear, step-by-step approach. This solution explores key algebraic concepts such as inequality manipulation and solving for x. Perfect for students in Grades 6-8 studying inequalities in algebra.

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