To solve the inequality:

$-1 < 2x + 3$

Step 1: Subtract 3 from both sides

$-1 - 3 < 2x$ $-4 < 2x$

Step 2: Divide both sides by 2

$\frac{-4}{2} < x$ $-2 < x$

Thus, the solution is: $x > -2$

The solution can also be written as: $x \in (-2, \infty)$

Would you like more details on this, or do you have any other questions?

Here are 5 related questions you might consider:

1. How would you solve $-2x + 5 \leq 1$?
2. What happens if the inequality has $\geq$ or $\leq$?
3. Can inequalities have more than two terms? For example, $1 < 3x + 2 < 7$?
4. How do you solve a quadratic inequality like $x^2 - 4x \leq 0$?
5. How would you graph the solution of $-2 < x$?

Tip: When dividing or multiplying an inequality by a negative number, remember to flip the inequality sign.