Let's solve the inequality:

\[
13q < 7q - 29
\]

### Step 1: Move the \( q \)-terms to one side.

Subtract \( 7q \) from both sides:

\[
13q - 7q < -29
\]

This simplifies to:

\[
6q < -29
\]

### Step 2: Solve for \( q \).

To isolate \( q \), divide both sides by 6:

\[
q < \frac{-29}{6}
\]

So, the solution is:

\[
q < -\frac{29}{6}
\]

### Final answer:
\[
q < -\frac{29}{6}
\]

Let me know if you would like more details, or if you have any questions!

Here are some related questions to further explore:
1. What is the solution to \( 5x > 2x + 9 \)?
2. How do you solve \( 10p - 4p \leq 20 + p \)?
3. What are the steps to solve \( 2n + 15 > 3n + 9 \)?
4. How do inequalities change when multiplying both sides by a negative number?
5. How would the solution change if we had \( 13q \leq 7q - 29 \)?

**Tip:** When solving inequalities, be cautious when multiplying or dividing by negative numbers, as it reverses the inequality sign.

Learn how to solve the linear inequality 13q < 7q - 29 step by step. This problem involves subtracting and isolating variables in inequalities and dividing by constants, suitable for students in Grades 8-10.

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