Math Problem Statement
jawaban
Solution
The question in the image asks to determine the solution set for each linear inequality with two variables. Let's analyze and solve each inequality one by one:
Given Inequalities:
-
(a)
Rearrange for : This inequality describes the region above the line (not including the line). -
(b)
Rearrange for : This inequality describes the region below the line . -
(c)
Rearrange for : This inequality describes the region below or on the line . -
(d)
Rearrange for : This inequality describes the region above or on the line . -
(e)
Rearrange for : This inequality describes the region above or on the line . -
(f)
Rearrange for : This inequality describes the region below or on the line . -
(g)
Rearrange for : This inequality describes the region below the line . -
(h)
Rearrange for : This inequality describes the region above the line .
Steps to Determine the Solution Set:
- For each inequality, graph the corresponding line.
- Shade the region specified by the inequality (above, below, or including the line).
- The solution set for all inequalities combined is the intersection of the shaded regions if multiple inequalities are considered.
Would you like me to graph these inequalities for visual clarity, or do you need a detailed solution for a specific inequality? Let me know!
Follow-up Questions:
- How do you identify the boundary line of a linear inequality?
- What is the role of testing a point (e.g., ) in determining the solution region?
- Can a solution set of inequalities be empty? Why?
- How does flipping the inequality sign affect the solution?
- What are real-world applications of systems of linear inequalities?
Tip:
When solving inequalities, always double-check if the inequality is strict () or includes equality () to correctly interpret the solution region!
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Math Problem Analysis
Mathematical Concepts
Linear Inequalities
Graphing Linear Equations
Intersection of Regions
Formulas
y = mx + c (Slope-Intercept Form)
Theorems
Linear inequality solution regions
Boundary lines and shading
Suitable Grade Level
Grades 9-11
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