Math Problem Statement

2a+3b , a=3 , b=-2

Solution

To solve the expression 2a+3b2a + 3b given a=3a = 3 and b=2b = -2:

Substitute the values of aa and bb into the expression:

2(3)+3(2)2(3) + 3(-2)

Now, calculate each part:

2(3)=62(3) = 6 3(2)=63(-2) = -6

Add them together:

6+(6)=06 + (-6) = 0

So, the value of the expression is 00.

Would you like more details or have any questions?


Here are 5 related questions to explore further:

  1. What happens if both aa and bb are negative?
  2. How do you factor an expression like 2a+3b2a + 3b?
  3. How can this expression change if aa and bb are functions instead of constants?
  4. What is the result of 2a+3b2a + 3b if a=3a = -3 and b=2b = 2?
  5. How does the distributive property work for expressions like this?

Tip: Always double-check the signs of the numbers you substitute to avoid common mistakes.

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Expressions
Substitution

Formulas

2a + 3b

Theorems

Distributive Property

Suitable Grade Level

Grades 6-8