Let's solve the given expressions for $a = 3$ and $b = -2$:

a. $2a - 5$

Substitute $a = 3$:

$2(3) - 5 = 6 - 5 = 1$

So, the result for part a is $1$.

b. $3b + 4a$

Substitute $b = -2$ and $a = 3$:

$3(-2) + 4(3) = -6 + 12 = 6$

So, the result for part b is $6$.

Final answers:

• a. $2a - 5 = 1$
• b. $3b + 4a = 6$

Would you like more details on any part of this?

Here are 5 related questions for further practice:

1. What is the value of $5a - 2b$ for $a = 3$ and $b = -2$?
2. Evaluate $a^2 + b^2$ with $a = 3$ and $b = -2$.
3. Calculate $4b - a^2$ for the same values of $a$ and $b$.
4. Find $7a + b^3$ using $a = 3$ and $b = -2$.
5. Simplify and evaluate $a(b + a)$ when $a = 3$ and $b = -2$.

Tip: Always double-check your substitutions to ensure accuracy when plugging in values.