https://file.aiquickdraw.com/mathbot/file/1730356904441ipw7qgyz.jpg

Let's solve each equation:

### (i) \( x + 7 = 15 \)

1. Subtract \( 7 \) from both sides to isolate \( x \):
   \[
   x = 15 - 7
   \]
2. Simplify:
   \[
   x = 8
   \]

So, the solution for (i) is \( x = 8 \).

---

### (ii) \( 5(3x + 8) = 10 \)

1. First, divide both sides by \( 5 \) to simplify:
   \[
   3x + 8 = \frac{10}{5}
   \]
   \[
   3x + 8 = 2
   \]

2. Next, subtract \( 8 \) from both sides:
   \[
   3x = 2 - 8
   \]
   \[
   3x = -6
   \]

3. Finally, divide by \( 3 \) to solve for \( x \):
   \[
   x = \frac{-6}{3}
   \]
   \[
   x = -2
   \]

So, the solution for (ii) is \( x = -2 \).

---

### Summary of Solutions
- (i) \( x = 8 \)
- (ii) \( x = -2 \)

Would you like further details on these solutions or have any questions?

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### Additional Practice Questions:
1. Solve \( x - 5 = 10 \).
2. Solve \( 4(2x + 3) = 20 \).
3. Solve \( 7x + 10 = 24 \).
4. Solve \( x/4 + 6 = 3 \).
5. Solve \( 2(x + 7) = 6 \).

**Tip:** When solving linear equations, aim to isolate \( x \) by performing inverse operations step-by-step.

Solve the equations: (i) x + 7 = 15, (ii) 5(3x + 8) = 10

Learn how to solve linear equations such as x + 7 = 15 and 5(3x + 8) = 10. This solution breaks down each step, showing how to isolate x and solve for it. Suitable for students in Grade 6-8.

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