Tyshawn took a taxi from his house to the airport. The taxi company charged a pick-up fee of $2.50 plus $3.50 per mile. The total fare was $79.50, not including the tip. Which equation could be used to determine m*m*, the number of miles in the taxi ride?

Answer

Multiple Choice Answers

79, point, 5, equals, 3, point, 5, plus, 2, point, 5, m79.5=3.5+2.5*m*

3, point, 5, m, equals, 2, point, 5, minus, 79, point, 53.5*m*=2.5−79.5

3, point, 5, m, equals, 79, point, 5, minus, 2, point, 53.5*m*=79.5−2.5

m, equals, start fraction, 7, 9, point, 5, minus, 3, point, 5, divided by, 2, point, 5, end fraction*m*=2.521​21​​79.5−3.5​

The taxi fare consists of a pick-up fee of $2.50 plus $3.50 per mile, and the total fare is $79.50. 

The equation for the total fare can be written as:

\[
\text{Total Fare} = \text{Pick-up Fee} + (\text{Cost per Mile} \times \text{Number of Miles})
\]

Substituting the given values:

\[
79.50 = 2.50 + 3.50m
\]

To solve for $m$, the correct equation is:

\[
3.50m = 79.50 - 2.50
\]

Thus, the correct answer is:

\[
\boxed{3.5m = 79.5 - 2.5}
\]

Do you need further explanation or details on this problem?

Here are 5 related questions:
1. How would the equation change if the pick-up fee were doubled?
2. What if the total fare were $100 instead of $79.50?
3. How would you solve for $m$ after setting up the equation?
4. What happens if the taxi company increases the cost per mile to $4?
5. How does adding a tip affect the total fare?

**Tip**: Always isolate the variable (in this case, $m$) by performing inverse operations to simplify equations.

Tyshawn took a taxi from his house to the airport. The taxi company charged a pick-up fee of $2.50 plus $3.50 per mile. The total fare was $79.50, not including the tip. Which equation could be used to determine m, the number of miles in the taxi ride?

Understand how to calculate the number of miles Tyshawn traveled based on a taxi fare problem. This algebraic problem involves setting up and solving a linear equation to find the distance, suitable for students in Grades 6-8.

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