Math Problem Statement

solve these

Solution

Let's solve each of the given equations step by step.

4. 12(b+2)=8(b+5)12(b + 2) = 8(b + 5)

  1. Distribute the constants on both sides: 12b+24=8b+4012b + 24 = 8b + 40
  2. Move the terms involving bb to one side: 12b8b=402412b - 8b = 40 - 24 4b=164b = 16
  3. Solve for bb: b=4b = 4

5. 6(y+8)=3(2y7)6(y + 8) = 3(2y - 7)

  1. Distribute the constants: 6y+48=6y216y + 48 = 6y - 21
  2. Subtract 6y6y from both sides: 48=2148 = -21 This is a contradiction, so there is no solution.

6. 34(12c4)=15c+15\frac{3}{4}(12c - 4) = 15c + 15

  1. Distribute 34\frac{3}{4}: 9c3=15c+159c - 3 = 15c + 15
  2. Move the terms involving cc to one side: 9c15c=15+39c - 15c = 15 + 3 6c=18-6c = 18
  3. Solve for cc: c=3c = -3

7. 11(4p+4)4p=4(7p7)11(4p + 4) - 4p = 4(7p - 7)

  1. Distribute on both sides: 44p+444p=28p2844p + 44 - 4p = 28p - 28
  2. Combine like terms: 40p+44=28p2840p + 44 = 28p - 28
  3. Move the terms involving pp to one side: 40p28p=284440p - 28p = -28 - 44 12p=7212p = -72
  4. Solve for pp: p=6p = -6

8. 3(2d8)=11d18(d3)3(2d - 8) = 11d - 18(d - 3)

  1. Distribute on both sides: 6d24=11d18d+546d - 24 = 11d - 18d + 54 6d24=7d+546d - 24 = -7d + 54
  2. Move the terms involving dd to one side: 6d+7d=54+246d + 7d = 54 + 24 13d=7813d = 78
  3. Solve for dd: d=6d = 6

9. 5(4+r)=12(40+10r)5(4 + r) = \frac{1}{2}(40 + 10r)

  1. Distribute on both sides: 20+5r=20+5r20 + 5r = 20 + 5r
  2. The equation simplifies to: 20+5r=20+5r20 + 5r = 20 + 5r This is an identity, so any value of rr will satisfy the equation.

10. 35e6=25(e10)7\frac{3}{5}e - 6 = \frac{2}{5}(e - 10) - 7

  1. Distribute the fractions: 35e6=25e47\frac{3}{5}e - 6 = \frac{2}{5}e - 4 - 7 35e6=25e11\frac{3}{5}e - 6 = \frac{2}{5}e - 11
  2. Move the terms involving ee to one side: 35e25e=11+6\frac{3}{5}e - \frac{2}{5}e = -11 + 6 15e=5\frac{1}{5}e = -5
  3. Solve for ee: e=25e = -25

11. Three consecutive integers are nn, n+1n + 1, and n+2n + 2. Four times the sum of the least and greatest integers is 12 less than three times the least integer. What is the least integer?

  1. Express the sum of the least and greatest integers: Sum=n+(n+2)=2n+2\text{Sum} = n + (n + 2) = 2n + 2
  2. Four times the sum: 4(2n+2)=8n+84(2n + 2) = 8n + 8
  3. Set up the equation based on the problem: 8n+8=3n128n + 8 = 3n - 12
  4. Move the terms involving nn to one side: 8n3n=1288n - 3n = -12 - 8 5n=205n = -20
  5. Solve for nn: n=4n = -4

Would you like a detailed explanation for any of these solutions or have any questions?

Related Questions:

  1. How do you solve systems of linear equations?
  2. What are the different types of equations encountered in algebra?
  3. Can you solve quadratic equations by factoring?
  4. What is the method of substitution in solving linear equations?
  5. How do you interpret the solution of a linear equation graphically?

Tip:

Always verify your solutions by substituting them back into the original equations to ensure they satisfy all given conditions.

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Math Problem Analysis

Mathematical Concepts

Linear equations
Distributive property
Solving equations

Formulas

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Theorems

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Suitable Grade Level

Grades 7-9