Math Problem Statement

options are A. X+Y = 7 B. 4X+3Y =24 C. 3X-4Y =12 D. NONE

Solution

To solve this problem, let's use the intercept form of the equation of a line. The intercept form is given by:

xa+yb=1\frac{x}{a} + \frac{y}{b} = 1

where aa is the x-intercept and bb is the y-intercept of the line. Given the information:

  1. The line passes through the point (6,7)(6, 7).
  2. The sum of the intercepts on the axes is 12, so a+b=12a + b = 12.

Let's substitute the point (6,7)(6, 7) into the intercept form:

6a+7b=1\frac{6}{a} + \frac{7}{b} = 1

Now, we also know a+b=12a + b = 12. We can solve these two equations simultaneously.

Step-by-Step Solution:

  1. Equation for the sum of intercepts:

a+b=12    b=12aa + b = 12 \implies b = 12 - a

  1. Substitute bb in the intercept form:

6a+712a=1\frac{6}{a} + \frac{7}{12 - a} = 1

  1. Find a common denominator and solve for aa:

6(12a)+7aa(12a)=1\frac{6(12 - a) + 7a}{a(12 - a)} = 1

6(12a)+7a=a(12a)6(12 - a) + 7a = a(12 - a)

726a+7a=12aa272 - 6a + 7a = 12a - a^2

a211a+72=0a^2 - 11a + 72 = 0

  1. Solve the quadratic equation:

The quadratic equation a211a+72=0a^2 - 11a + 72 = 0 can be factored as:

(a8)(a9)=0(a - 8)(a - 9) = 0

Thus, a=8a = 8 or a=9a = 9.

  1. Find corresponding bb values:

If a=8a = 8, then b=128=4b = 12 - 8 = 4.
If a=9a = 9, then b=129=3b = 12 - 9 = 3.

Equations of the Lines:

For a=8a = 8 and b=4b = 4:

x8+y4=1    4x+8y=32    4x+3y=24(dividing by 2)\frac{x}{8} + \frac{y}{4} = 1 \implies 4x + 8y = 32 \implies 4x + 3y = 24 \quad (\text{dividing by 2})

For a=9a = 9 and b=3b = 3:

x9+y3=1    3x+9y=27    x+3y=9\frac{x}{9} + \frac{y}{3} = 1 \implies 3x + 9y = 27 \implies x + 3y = 9

Compare with the Options:

  • Option A: x+y=7x + y = 7 — Not correct.
  • Option B: 4x+3y=244x + 3y = 24 — Correct.
  • Option C: 3x4y=123x - 4y = 12 — Not correct.
  • Option D: None — Not correct.

The correct answer is Option B: 4x+3y=244x + 3y = 24.

Would you like more details or have any questions?

Related Questions:

  1. How do you determine the intercept form of a line?
  2. Can a line have negative intercepts, and how does it affect its equation?
  3. How do you find the equation of a line given two points instead of intercepts?
  4. What is the general form of a linear equation, and how can you convert between different forms?
  5. What methods can be used to solve a quadratic equation like a211a+72=0a^2 - 11a + 72 = 0?

Tip:

When dealing with linear equations and intercepts, remember that intercepts represent where the line crosses the axes, and can help visualize the line's slope and position in the coordinate plane.

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Math Problem Analysis

Mathematical Concepts

Linear equations
Intercepts
Simultaneous equations

Formulas

Intercept form of a line
Quadratic equation solving

Theorems

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Suitable Grade Level

Grades 9-12