To solve the equation \( 20 + 4c = 6c - n \) for \( n \), follow these steps:

1. **Isolate** the term containing \( n \) on one side of the equation. Start by subtracting \( 6c \) from both sides:
   \[
   20 + 4c - 6c = -n
   \]

2. **Simplify** the equation:
   \[
   20 - 2c = -n
   \]

3. **Solve for \( n \)** by multiplying both sides by -1:
   \[
   n = -20 + 2c
   \]

Thus, the solution is:
\[
n = 2c - 20
\]

Would you like more details or have any other questions? 

Here are 5 related questions:

1. What steps can be taken to verify the solution for \( n \)?
2. How would the solution change if the equation was \( 20 + 4c = 6c + n \)?
3. What is the significance of isolating the variable when solving an equation?
4. How can we interpret the equation \( n = 2c - 20 \) in a real-world context?
5. Can you graph the relationship between \( c \) and \( n \) as defined by \( n = 2c - 20 \)?

**Tip:** Always check your final solution by substituting it back into the original equation. This ensures your solution is correct.

Learn how to solve the linear equation 20 + 4c = 6c - n step-by-step. This problem involves isolating variables and simplifying equations, essential concepts in algebra. Suitable for high school students.

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