To solve the equation \(-20c - 2c - 6 = 16\), we can follow these steps:

### Step 1: Combine like terms
The terms \(-20c\) and \(-2c\) are like terms because they both contain the variable \(c\).

\[
-20c - 2c = -22c
\]

So the equation simplifies to:

\[
-22c - 6 = 16
\]

### Step 2: Isolate the variable term
Add 6 to both sides of the equation to move the constant term to the right side:

\[
-22c = 16 + 6
\]

\[
-22c = 22
\]

### Step 3: Solve for \(c\)
Divide both sides of the equation by \(-22\) to solve for \(c\):

\[
c = \frac{22}{-22} = -1
\]

### Final Answer
The solution is \(c = -1\).

Would you like more details or have any questions?

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**Related Questions:**

1. How would the solution change if the equation was \(-20c - 2c - 6 = -16\)?
2. What happens if you multiply the entire equation by a constant before solving?
3. How would you check the solution to this equation?
4. What is the significance of combining like terms in an equation?
5. How do you solve an equation where the variable term is on both sides?
6. Can you solve for \(c\) if the equation was \(-20c - 2c + 6 = 16\)?
7. How would the steps differ if there were multiple variables?
8. What happens if the constant term was a fraction?

**Tip:** Always double-check your solution by substituting it back into the original equation to ensure it satisfies the equation.

Learn how to solve the equation -20c - 2c - 6 = 16 step-by-step. This problem involves combining like terms and isolating the variable to find its value. Suitable for students in Grades 7-9 studying algebra and equations.

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