https://file.aiquickdraw.com/mathbot/file/1726772151057qq3hk7gj.jpg

Let's solve the two given equations.

1. **First equation:**

   \[
   15 = -3n
   \]

   To solve for \( n \), divide both sides of the equation by \(-3\):

   \[
   n = \frac{15}{-3} = -5
   \]

2. **Second equation:**

   \[
   \frac{x}{4} = 8
   \]

   To solve for \( x \), multiply both sides of the equation by 4:

   \[
   x = 8 \times 4 = 32
   \]

### Final solutions:
- \( n = -5 \)
- \( x = 32 \)

Would you like further details or have any questions?

Here are five related questions:
1. What happens if we change the coefficient of \( n \) in the first equation to \(-6\)?
2. Can you solve for \( n \) if the first equation becomes \( 15 = 3n \)?
3. What if the second equation was \( \frac{x}{5} = 8 \)? What would \( x \) be?
4. How would you solve the equation \( 2x - 5 = 3x + 7 \)?
5. Can you graph the equation \( \frac{x}{4} = 8 \) on a coordinate plane?

### Tip:
When solving equations, always aim to isolate the variable on one side of the equation by performing inverse operations.

What is the solution for these two equations: 15 = -3n and x/4 = 8?

This page provides step-by-step solutions for two linear equations: 15 = -3n and x/4 = 8. The solution covers core algebraic concepts like isolating the variable and solving for unknowns. Suitable for students in Grades 6-8.

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