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The given equation is:

\[
v_2 = v_1 + at
\]

We need to solve for \( t \). To do so, let's isolate \( t \) on one side of the equation.

### Steps:

1. Subtract \( v_1 \) from both sides:

\[
v_2 - v_1 = at
\]

2. Now, divide both sides by \( a \) to solve for \( t \):

\[
t = \frac{v_2 - v_1}{a}
\]

Thus, the solution for \( t \) is:

\[
t = \frac{v_2 - v_1}{a}
\]

Would you like further clarification, or do you have any specific questions on this?

Here are 5 related questions to expand your understanding:

1. How does the acceleration \( a \) affect the value of \( t \)?
2. If \( v_2 = 0 \), how would the equation change, and what does this mean in terms of the physical context?
3. Can you derive this formula from the laws of kinematics?
4. What happens if \( a = 0 \)? How would you interpret that scenario?
5. How can this equation be applied in a real-world scenario, such as a car speeding up?

**Tip:** Remember that acceleration \( a \) must be non-zero for the equation to be meaningful; otherwise, dividing by zero is undefined!

Solve the following equation for t: v2 = v1 + at

Learn how to solve the equation v2 = v1 + at for t. This problem involves fundamental algebra and kinematic equations, covering the first equation of motion. Suitable for students in Grades 9-12.

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