Math Problem Statement

Solve bx - 3b + 6 = 0.

Solution

The image asks to solve the equation:

bx3b+6=0bx - 3b + 6 = 0

Let's solve this equation step by step.

Step 1: Isolate the term involving xx

First, subtract 6 from both sides to move the constant term:

bx3b=6bx - 3b = -6

Step 2: Solve for xx

Now, add 3b3b to both sides:

bx=3b6bx = 3b - 6

Finally, divide both sides by bb (assuming b0b \neq 0):

x=3b6bx = \frac{3b - 6}{b}

Step 3: Simplify the expression

We can simplify this by dividing each term in the numerator by bb:

x=36bx = 3 - \frac{6}{b}

So the solution for xx is:

x=36b\boxed{x = 3 - \frac{6}{b}}

Would you like further details on the steps or have any questions?


Related Questions:

  1. What happens to the value of xx as bb approaches zero?
  2. How would the solution change if the equation had an additional constant term on the right side?
  3. Can you graph the relationship between xx and bb based on the solution?
  4. What are the implications if b=0b = 0?
  5. How would you solve the equation if it were quadratic, such as bx23b+6=0bx^2 - 3b + 6 = 0?

Tip: When simplifying fractions, always check if each term can be divided by the common denominator to reduce the expression.

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations

Formulas

Linear equation formula ax + b = 0

Theorems

Properties of Linear Equations

Suitable Grade Level

Grades 8-10