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The equation provided is:

\[
3 - (-b) = 6
\]

To solve for \( b \), follow these steps:

1. Simplify the equation. Since subtracting a negative is the same as adding, the equation becomes:
   \[
   3 + b = 6
   \]

2. Subtract 3 from both sides to isolate \( b \):
   \[
   b = 6 - 3
   \]

3. Simplify the right-hand side:
   \[
   b = 3
   \]

So, the solution is \( b = 3 \).

Would you like more details or have any questions?

Here are some related questions you might find interesting:
1. How can you solve equations with variables on both sides?
2. What happens if there are fractions in the equation?
3. How do you solve equations with exponents?
4. How can you check your solution to ensure it's correct?
5. What are common mistakes when solving linear equations?

**Tip:** Always double-check your steps by plugging the value of the variable back into the original equation.

Learn how to solve the linear equation 3 - (-b) = 6 with a detailed step-by-step solution. This problem covers basic algebraic concepts and negative number operations. Suitable for students in Grades 6-8.

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