Let's solve the equation:

\[
6(2y + 3) = 42
\]

### Step 1: Distribute the 6
\[
6 \times 2y + 6 \times 3 = 42
\]
\[
12y + 18 = 42
\]

### Step 2: Subtract 18 from both sides
\[
12y = 42 - 18
\]
\[
12y = 24
\]

### Step 3: Divide both sides by 12
\[
y = \frac{24}{12}
\]
\[
y = 2
\]

Thus, the solution is:

\[
y = 2
\]

Would you like more details on any of the steps? 

Here are some related questions:
1. How do you solve equations with fractions?
2. How would you solve if the equation had multiple variables?
3. What happens if the equation includes negative numbers?
4. How do you verify the solution to an equation?
5. Can you explain how distributive property works in general?

**Tip:** Always simplify both sides of an equation as much as possible before solving.

Learn how to solve the linear equation 6(2y + 3) = 42 step by step, applying the distributive property and basic algebraic principles. Suitable for students in Grades 6-8, this problem helps build foundational algebra skills.

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