Let's solve the equation \( 2(6 - 3x) = 6 \).

1. First, distribute the 2 on the left-hand side:
\[
2(6 - 3x) = 2 \cdot 6 - 2 \cdot 3x = 12 - 6x
\]
Now the equation becomes:
\[
12 - 6x = 6
\]

2. Subtract 12 from both sides to isolate the term with \(x\):
\[
12 - 6x - 12 = 6 - 12
\]
\[
-6x = -6
\]

3. Divide both sides by \(-6\) to solve for \(x\):
\[
x = \frac{-6}{-6} = 1
\]

So, the solution is \( x = 1 \).

Would you like more details or have any questions?

---

Here are 5 related questions to consider:
1. What happens if you change the constant on the right-hand side, say \(2(6 - 3x) = 10\)?
2. How would you solve \(3(4 - 2x) = 9\)?
3. What are the steps to solve \(5 - 2x = 3x + 7\)?
4. Can you solve \(4x - 3(2 - x) = 7\)?
5. How do you solve \(6(2 - x) = 2(x + 3)\)?

**Tip:** Always perform the distribution step carefully when solving equations involving parentheses.

Discover the step-by-step solution to solving the linear equation 2(6 - 3x) = 6 using the distributive property and basic properties of equality. Ideal for students in Grades 6-8 who want to strengthen their algebraic problem-solving skills.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation