Let's solve the equation $2(6 - 3x) = 6$.

1. First, distribute the 2 on the left-hand side: $2(6 - 3x) = 2 \cdot 6 - 2 \cdot 3x = 12 - 6x$ Now the equation becomes: $12 - 6x = 6$

2. Subtract 12 from both sides to isolate the term with $x$: $12 - 6x - 12 = 6 - 12$ $-6x = -6$

3. Divide both sides by $-6$ to solve for $x$: $x = \frac{-6}{-6} = 1$

So, the solution is $x = 1$.

Would you like more details or have any questions?

---

Here are 5 related questions to consider:

1. What happens if you change the constant on the right-hand side, say $2(6 - 3x) = 10$?
2. How would you solve $3(4 - 2x) = 9$?
3. What are the steps to solve $5 - 2x = 3x + 7$?
4. Can you solve $4x - 3(2 - x) = 7$?
5. How do you solve $6(2 - x) = 2(x + 3)$?

Tip: Always perform the distribution step carefully when solving equations involving parentheses.