To solve the equation \(5x - 11 = 19 - x\), let's follow these steps:

1. **Combine like terms**: First, we'll move all the terms involving \(x\) to one side and the constant terms to the other side.
   
   \[
   5x + x = 19 + 11
   \]

   This simplifies to:

   \[
   6x = 30
   \]

2. **Solve for \(x\)**: Now, divide both sides by 6 to isolate \(x\).

   \[
   x = \frac{30}{6}
   \]

   Which simplifies to:

   \[
   x = 5
   \]

So, the solution to the equation \(5x - 11 = 19 - x\) is \(x = 5\).

Would you like more details or have any questions?

### Related Questions:

1. How would you solve the equation \(7x - 15 = 3x + 9\)?
2. What happens if the equation involves fractions, like \(\frac{3}{2}x - 4 = \frac{5}{3}x + 2\)?
3. How can you solve a quadratic equation, such as \(x^2 - 5x + 6 = 0\)?
4. What is the method to solve a system of linear equations, like \(2x + 3y = 7\) and \(4x - y = 5\)?
5. Can we apply the same approach to solve inequalities, such as \(5x - 11 > 19 - x\)?

### Tip:
Always double-check your solution by substituting it back into the original equation to ensure both sides are equal.

Learn how to solve the linear equation 5x - 11 = 19 - x with a detailed step-by-step guide. This problem covers key algebraic concepts like combining like terms and using the properties of equality, making it ideal for students in Grades 6-8.

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