To solve the equation \( 3g - 10 = 6g + 8 \), let's follow these steps:

1. **Move the terms involving \( g \) to one side**:  
   Subtract \( 3g \) from both sides:
   \[
   -10 = 3g + 8
   \]

2. **Move the constants to the other side**:  
   Subtract 8 from both sides:
   \[
   -10 - 8 = 3g
   \]
   \[
   -18 = 3g
   \]

3. **Solve for \( g \)**:  
   Divide both sides by 3:
   \[
   g = \frac{-18}{3} = -6
   \]

Thus, the solution is \( g = -6 \).

Would you like more details on any step?

Here are 5 related questions:
1. What happens if we add the same value to both sides of an equation?
2. How do we check if a solution to an equation is correct?
3. Can this method of solving work for inequalities as well?
4. What is the difference between a linear equation and a quadratic equation?
5. How can you graph the equation \( 3g - 10 = 6g + 8 \)?

**Tip:** Always double-check your solution by substituting it back into the original equation to ensure both sides are equal.

Learn how to solve the linear equation 3g - 10 = 6g + 8 with a step-by-step solution. This problem covers essential algebra concepts, such as moving terms, isolating variables, and dividing to find the value of g. Suitable for students in Grades 6-8.

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