https://file.aiquickdraw.com/mathbot/file/1729140928024bn7qkqff.jpg

The equation in the image is:

\[
15 = 1.5r + 3
\]

### Let's solve for \( r \):

1. Subtract 3 from both sides to isolate the term with \( r \):

\[
15 - 3 = 1.5r
\]
\[
12 = 1.5r
\]

2. Now, divide both sides by 1.5 to solve for \( r \):

\[
r = \frac{12}{1.5}
\]
\[
r = 8
\]

### Solution:
\[
r = 8
\]

Would you like more details on this solution, or have any questions?

Here are some related questions for further practice:
1. What if the equation was \(15 = 2r + 3\)?
2. How would you solve \(15 = 3r + 3\)?
3. What is the process if \(15 = 1.5r - 3\)?
4. Can you solve \(15 = 0.5r + 3\)?
5. What is the result for \(15 = 1.5r + 5\)?

**Tip:** When solving linear equations, always perform the same operation on both sides to maintain balance!

Learn how to solve the linear equation 15 = 1.5r + 3 with a step-by-step solution. This example covers key algebraic concepts, including isolating variables and solving for r. Suitable for students in Grades 6-8.

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