To solve the equation \( 15 = 3(n + 1) \), follow these steps:

1. Distribute the 3 on the right-hand side:
   \[
   15 = 3n + 3
   \]

2. Subtract 3 from both sides to isolate the term with \( n \):
   \[
   15 - 3 = 3n
   \]
   \[
   12 = 3n
   \]

3. Divide both sides by 3 to solve for \( n \):
   \[
   n = \frac{12}{3} = 4
   \]

Thus, the solution is \( n = 4 \).

Would you like more details or further clarification?

Here are five related questions to explore:

1. How would the solution change if the equation were \( 15 = 4(n + 1) \)?
2. Can you solve \( 20 = 5(n - 2) \) in a similar manner?
3. What if the equation was \( 15 = 3(2n + 1) \)? How would you solve for \( n \)?
4. How does distributing a negative number in equations like \( -15 = -3(n + 1) \) work?
5. Can you explain how solving inequalities differs from solving equalities?

**Tip:** Always perform the same operation on both sides of the equation to maintain balance!

Learn how to solve the linear equation 15 = 3(n + 1) with a detailed step-by-step explanation. This problem covers key algebraic concepts, including the distributive property and isolating variables. Ideal for students in Grades 6-8.

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