https://file.aiquickdraw.com/mathbot/file/1726454295871apnmj7n0.jpg

The equation in the image is:

\[
29 = r + 15
\]

To solve for \( r \):

1. Subtract 15 from both sides of the equation:
   \[
   29 - 15 = r
   \]
   \[
   r = 14
   \]

Thus, the solution is \( r = 14 \).

Would you like more details or have any other questions?

Here are 5 related questions:
1. What is the next step if the equation were \( 29 = r + 18 \)?
2. How would the solution change if it were \( 29 = 2r + 15 \)?
3. Can you solve \( 29 = r - 15 \) instead?
4. How would you isolate \( r \) if the equation were \( 2r + 15 = 29 \)?
5. What happens if the equation is \( 29 = r/2 + 15 \)?

**Tip:** Always perform the same operation on both sides of the equation to maintain equality when solving for a variable.

Learn how to solve the linear equation 29 = r + 15 with a simple step-by-step approach. This example covers essential algebra concepts, including solving for variables by isolating them through subtraction. Ideal for students in Grades 5-7.

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