The image you uploaded shows an example of solving an integral using substitution.

The problem is to evaluate the following integral: $\int_0^5 \frac{dx}{\sqrt[3]{2 - x}}$

The substitution method is used here. The substitution is: $u = 2 - x \quad \Rightarrow \quad du = -dx$

This transforms the integral into: $-\int_0^5 \frac{du}{u^{1/3}}$

Would you like to continue with the solution, or do you need more explanation on any step? Let me know if you need further assistance!

Further Related Questions:

1. How do we integrate $u^{-1/3}$?
2. What happens to the limits of integration when we perform a substitution?
3. How do you handle negative signs in integrals during substitution?
4. Can we use a different substitution for this type of integral?
5. How do you interpret the final result of this type of integral in terms of geometry?

Tip:

When using substitution, always carefully adjust the limits of integration to match the new variable. This ensures the result is accurate.