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The question asks how much Sarah initially invested if her stock grew by 22% to reach $427.

Let the initial investment be $ x $.

According to the problem, her investment grew by 22%, which means the final value is:

\[
x + 0.22x = 427
\]

Simplifying:

\[
1.22x = 427
\]

Now, solve for $ x $:

\[
x = \frac{427}{1.22}
\]

I will calculate that for you.Sarah initially invested $350.

Would you like more details or have any questions?

Here are 5 related questions you might find interesting:
1. What would Sarah's investment be if it grew by 30% instead of 22%?
2. How much would Sarah have if her investment grew by 50%?
3. What was the total increase in value for Sarah's investment?
4. If Sarah invested $400, how much would she have after a 22% growth?
5. How long would it take to double an investment growing at a 22% annual rate?

**Tip**: When calculating percentages, always multiply the initial amount by $ (1 + \text{growth rate}) $ for increases or $ (1 - \text{decrease rate}) $ for decreases.

Sarah's investment in stock grew 22% to $427. How much did she invest?

Learn how to calculate the initial investment when Sarah's stock grows by 22% to reach $427. This involves solving a percentage-based algebraic equation, suitable for students in Grades 7-9.

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