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The problem states:

> Sarah's investment in stock grew 16% to $348. How much did she invest?

Let's solve this step-by-step.

### Step 1: Let Sarah's initial investment be $ x $.

The value of her investment grew by 16%, which means:
\[
x + 0.16x = 348
\]
or equivalently:
\[
1.16x = 348
\]

### Step 2: Solve for $ x $.

To find $ x $, we divide both sides of the equation by 1.16:
\[
x = \frac{348}{1.16}
\]

Let's calculate that:
\[
x = 300
\]

### Conclusion:
Sarah initially invested **$300**.

Would you like more details on the calculation, or have any further questions? 

Here are 5 related questions to explore further:
1. What if Sarah's investment grew by 20% instead of 16%?
2. How much would she have if the investment grew by 25%?
3. If she initially invested $500, how much would it be after a 16% increase?
4. What would her initial investment be if the final amount was $500 after a 16% increase?
5. How can compound interest affect investments over multiple years?

**Tip:** When dealing with percentage increases, the formula is usually of the form $ \text{Initial Amount} \times (1 + \text{Growth Rate}) = \text{Final Amount} $.

Sarah's investment in stock grew 16% to $348. How much did she invest?

Learn how to calculate the initial investment given a 16% growth rate and a final value of $348. This problem demonstrates percentage growth and basic algebra, suitable for students in Grades 6-9.

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