If

⋅ (9x) ≥ 3, which of the following inequalities must be true?

The given inequality is:

\[
(9x) \geq 3
\]

To solve for \( x \), divide both sides of the inequality by 9:

\[
x \geq \frac{3}{9}
\]

Simplifying:

\[
x \geq \frac{1}{3}
\]

Therefore, the inequality that must be true is:

\[
x \geq \frac{1}{3}
\]

Would you like further details or have any questions?

Here are 5 related questions for further practice:
1. Solve the inequality \( 5x - 2 \geq 8 \).
2. What is the solution to \( 4x + 7 \leq 19 \)?
3. Solve \( \frac{x}{3} - 4 \leq 2 \).
4. What happens to the inequality if you multiply both sides by a negative number?
5. Solve \( 12x \geq 36 \).

**Tip**: When solving inequalities, remember that multiplying or dividing by a negative number reverses the inequality sign!

If (9x) ≥ 3, which of the following inequalities must be true?

Learn how to solve the inequality 9x ≥ 3 step-by-step. This problem focuses on algebraic concepts, including dividing both sides of an inequality and simplifying. It's suitable for students in Grades 6-8.

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