The given inequality is:

$(9x) \geq 3$

To solve for $x$, divide both sides of the inequality by 9:

$x \geq \frac{3}{9}$

Simplifying:

$x \geq \frac{1}{3}$

Therefore, the inequality that must be true is:

$x \geq \frac{1}{3}$

Would you like further details or have any questions?

Here are 5 related questions for further practice:

1. Solve the inequality $5x - 2 \geq 8$.
2. What is the solution to $4x + 7 \leq 19$?
3. Solve $\frac{x}{3} - 4 \leq 2$.
4. What happens to the inequality if you multiply both sides by a negative number?
5. Solve $12x \geq 36$.

Tip: When solving inequalities, remember that multiplying or dividing by a negative number reverses the inequality sign!