the sum of 5 and the twice a number is at most 27

The problem states: "The sum of 5 and twice a number is at most 27." Let's break it down into an inequality.

Let the unknown number be represented by \( x \).

1. "Twice a number" means \( 2x \).
2. "The sum of 5 and twice a number" is represented as \( 5 + 2x \).
3. "At most 27" means it is less than or equal to 27.

Thus, we can write the inequality as:
\[
5 + 2x \leq 27
\]

### Solving the inequality:
1. Subtract 5 from both sides:
\[
2x \leq 22
\]
2. Divide both sides by 2:
\[
x \leq 11
\]

Thus, the number \( x \) is at most 11.

Would you like more details or have any further questions?

Here are 5 related questions:
1. What if the sum of 5 and three times a number is at most 30?
2. How would the inequality change if it was "the sum of 5 and twice a number is at least 27"?
3. Can you solve the inequality: \( 7 + 3x \leq 40 \)?
4. What if the inequality was \( 4 + 2x > 16 \)?
5. How would you write the equation for "the difference of twice a number and 3 is less than 12"?

**Tip**: When solving inequalities, always reverse the inequality sign if you multiply or divide by a negative number.

Learn how to solve the inequality where the sum of 5 and twice a number is at most 27. This problem involves key algebraic concepts such as inequalities and solving linear equations. Suitable for students in Grades 6-8.

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