The problem states: "The sum of 5 and twice a number is at most 27." Let's break it down into an inequality.

Let the unknown number be represented by $x$.

1. "Twice a number" means $2x$.
2. "The sum of 5 and twice a number" is represented as $5 + 2x$.
3. "At most 27" means it is less than or equal to 27.

Thus, we can write the inequality as: $5 + 2x \leq 27$

Solving the inequality:

1. Subtract 5 from both sides: $2x \leq 22$
2. Divide both sides by 2: $x \leq 11$

Thus, the number $x$ is at most 11.

Would you like more details or have any further questions?

Here are 5 related questions:

1. What if the sum of 5 and three times a number is at most 30?
2. How would the inequality change if it was "the sum of 5 and twice a number is at least 27"?
3. Can you solve the inequality: $7 + 3x \leq 40$?
4. What if the inequality was $4 + 2x > 16$?
5. How would you write the equation for "the difference of twice a number and 3 is less than 12"?

Tip: When solving inequalities, always reverse the inequality sign if you multiply or divide by a negative number.