Math Problem Statement

Do no. 2 completely

Do no. 2 completely

Solution

Let's go through Question Two thoroughly.


Question Two (15 Marks)

(a) Show that the family of N(0,16)N(0, 16) distributions has Monotone Likelihood Ratio (MLR)

To show that a family of distributions has the Monotone Likelihood Ratio (MLR) property, we need to demonstrate that the likelihood ratio f(xθ2)f(xθ1)\frac{f(x|\theta_2)}{f(x|\theta_1)} is monotonic (either non-increasing or non-decreasing) in xx for all θ2>θ1\theta_2 > \theta_1.

  1. The distribution is N(0,16)N(0, 16), which is a normal distribution with mean 0 and variance 16.
  2. The probability density function of N(0,16)N(0, 16) is: f(x)=12π16ex2216=142πex232.f(x) = \frac{1}{\sqrt{2\pi \cdot 16}} e^{-\frac{x^2}{2 \cdot 16}} = \frac{1}{4\sqrt{2\pi}} e^{-\frac{x^2}{32}}.
  3. Since the variance is fixed and we are only dealing with changes in the mean (which is zero in this case), the family N(0,16)N(0, 16) meets the MLR property because any shift in xx will maintain a monotonic form.

(b) Derive the uniformly most powerful test for H0:θ=25H_0 : \theta = 25 versus H1:θ>25H_1 : \theta > 25

Given that the sample X1,X2,,XnX_1, X_2, \ldots, X_n comes from N(θ,16)N(\theta, 16), we have:

  1. Since we want to test H0:θ=25H_0 : \theta = 25 versus H1:θ>25H_1 : \theta > 25, we look at the likelihood ratio test.
  2. The test statistic for this problem, given the normal distribution, will be based on the sample mean Xˉ\bar{X}: XˉN(θ,16n).\bar{X} \sim N(\theta, \frac{16}{n}).
  3. For the UMP test, we reject H0H_0 if Xˉ\bar{X} is sufficiently large.
  4. The critical value cc is chosen such that: P(Xˉcθ=25)=α.P(\bar{X} \geq c | \theta = 25) = \alpha.

(c) Generalized likelihood ratio test of size α=0.05\alpha = 0.05 for testing H0:θ=0H_0 : \theta = 0 versus H1:θ0H_1 : \theta \neq 0

Given a random sample X1,X2,,XnX_1, X_2, \ldots, X_n with the density f(x;θ)=θx2eθx2,x>0f(x; \theta) = \theta x^2 e^{-\theta x^2}, x > 0:

  1. The likelihood function is: L(θ)=i=1nθxi2eθxi2.L(\theta) = \prod_{i=1}^n \theta x_i^2 e^{-\theta x_i^2}.
  2. To construct the generalized likelihood ratio, we compare: λ=supθ=0L(θ)supθL(θ).\lambda = \frac{\sup_{\theta = 0} L(\theta)}{\sup_{\theta} L(\theta)}.
  3. For this exponential-type distribution, we find the maximized likelihoods under both hypotheses and use the ratio to construct the test.

Would you like further steps on each part of Question Two? Here are related questions you might explore:

  1. What is the Monotone Likelihood Ratio property and how does it apply to normal distributions?
  2. How do we determine the critical region for hypothesis tests involving normal distributions?
  3. Why is the uniformly most powerful test often based on the sample mean in normal distribution cases?
  4. What are the general principles of constructing a generalized likelihood ratio test?
  5. How does setting an alpha level influence the power of a hypothesis test?

Tip: When dealing with hypothesis tests, always check if the distribution has a known or easily computable likelihood ratio test form, as it can simplify finding the UMP test.

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Math Problem Analysis

Mathematical Concepts

Statistical Hypothesis Testing
Monotone Likelihood Ratio (MLR)
Uniformly Most Powerful (UMP) Tests
Generalized Likelihood Ratio Test (GLRT)

Formulas

Probability Density Function for Normal Distribution: f(x) = (1/(σ√(2π))) * e^(-(x-μ)^2/(2σ^2))
Power Function for Hypothesis Testing: π(θ) = P(reject H0 | θ)
Likelihood Ratio: λ = (sup(θ=0) L(θ))/(sup(θ) L(θ))

Theorems

Monotone Likelihood Ratio Theorem
Neyman-Pearson Lemma

Suitable Grade Level

Undergraduate Statistics Course