Math Problem Statement

Let X1, X2, ..., Xn be a random sample from a Bernoulli distribution...

Solution

Let's go through each problem in the set and outline the key points for solving them.

Problem 1

  1. Distribution: X1,X2,,XnX_1, X_2, \dots, X_n is a sample from a Bernoulli distribution with pmf: f(x;θ)=θx(1θ)1x,x=0,1f(x; \theta) = \theta^x (1 - \theta)^{1 - x}, \quad x = 0, 1 where θ\theta is either 12\frac{1}{2} (null hypothesis H0H_0) or 13\frac{1}{3} (alternative hypothesis H1H_1).

  2. Goal: Show that the set C={(x1,,xn):i=1nxik}C = \left\{ (x_1, \dots, x_n) : \sum_{i=1}^n x_i \geq k \right\} forms the critical region for the most powerful test of size α\alpha for testing H0H_0 versus H1H_1.

  3. Approach:

    • Use the Neyman-Pearson Lemma, which gives the most powerful test by comparing the likelihood ratio to a threshold.
    • Calculate the likelihood ratio for the Bernoulli distribution with hypotheses values.
    • Determine the value of kk such that the test has size α\alpha.

Problem 2

  1. Distribution: X1,X2,,X10X_1, X_2, \dots, X_{10} is a sample from a Poisson distribution with mean θ\theta.

  2. Goal: Show that C={(x1,,x10):i=110xi3}C = \left\{ (x_1, \dots, x_{10}) : \sum_{i=1}^{10} x_i \geq 3 \right\} is the critical region of a most powerful test of size α=0.0803\alpha = 0.0803 for testing H0:θ=0.1H_0: \theta = 0.1 versus H0:θ=0.5H_0: \theta = 0.5.

  3. Approach:

    • Apply the Neyman-Pearson Lemma for Poisson distributions.
    • Compute the probability of the test statistic under H0H_0 to verify that the size is 0.08030.0803.
    • Determine whether i=110Xi\sum_{i=1}^{10} X_i satisfies the necessary conditions for the test.

Problem 3

  1. Distribution: X1,X2,,XnX_1, X_2, \dots, X_n is a sample from a normal distribution N(θ,2)N(\theta, 2) with unknown mean θ\theta.

  2. Goal: Derive the most powerful test of size α\alpha for testing H0:θ=1H_0: \theta = -1 versus H1:θ=1H_1: \theta = 1.

  3. Approach:

    • Use the Neyman-Pearson Lemma again to derive the likelihood ratio test.
    • Simplify the test to its implementable form, focusing on the statistic that depends linearly on θ\theta.
    • Determine the critical region by finding the appropriate test statistic and comparing it to a threshold for size α\alpha.

Problem 4

  1. Distribution: A single observation XX from the density function: f(x;θ)=(2θx+1θ),0<x<1f(x; \theta) = (2 \theta x + 1 - \theta), \quad 0 < x < 1 with 1θ1-1 \leq \theta \leq 1.

  2. Goal: Find the most powerful size α\alpha test of H0:θ=0H_0: \theta = 0 versus H1:θ=1H_1: \theta = 1.

  3. Approach:

    • Compute the likelihood ratio for the density under H0H_0 and H1H_1.
    • Apply the Neyman-Pearson Lemma to determine the critical region in terms of XX for a test of size α\alpha.
    • Verify that the resulting test satisfies the Neyman-Pearson criterion.

Would you like me to go into detailed solutions for each problem?


Follow-up Questions

  1. How does the Neyman-Pearson Lemma determine the form of a most powerful test?
  2. What are the steps to calculate the likelihood ratio for hypothesis testing?
  3. In Problem 2, why is the sum of Poisson-distributed random variables used as a test statistic?
  4. How do you determine the test size α\alpha in the context of these hypothesis tests?
  5. What role does the critical region play in the context of most powerful tests?

Tip

For hypothesis tests involving composite hypotheses, consider how the likelihood ratio varies across the parameter space to identify uniformly most powerful (UMP) tests if possible.

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Math Problem Analysis

Mathematical Concepts

Hypothesis Testing
Neyman-Pearson Lemma
Critical Region
Most Powerful Test

Formulas

f(x; θ) = θ^x (1 - θ)^(1 - x) for Bernoulli distribution
C = { (x1, ..., xn) : Σ xi ≥ k } for critical region
Likelihood ratio for most powerful test

Theorems

Neyman-Pearson Lemma

Suitable Grade Level

Undergraduate