Math Problem Statement

Solve 6

Solve for the height of the poles AB and CD, which are standing opposite each other on the ground with a distance of 60 meters between them. The angle of depression from point A to point D is 30°, and the angle of elevation from point D to point A is 60°.

Solution

For Question 6 on the image:

The problem appears to involve two poles, ABAB and CDCD, that are of equal height and standing opposite each other on the ground, which is 60 meters wide. The angles of depression and elevation are given, and we are required to find the height of the pole CDCD.

Given Information:

  • The distance between the poles is 60 meters.
  • Angle of depression from point AA (top of pole ABAB) to point DD (bottom of pole CDCD) is 3030^\circ.
  • Angle of elevation from point DD (bottom of pole CDCD) to point AA (top of pole ABAB) is 6060^\circ.

Let's break down the steps to solve the problem using trigonometric relationships.

Step-by-step Solution

  1. Label the diagram: Let the height of both poles be hh.

  2. Using the angle of depression (30°):

    • Since the angle of depression from AA to DD is 3030^\circ, the corresponding angle of elevation from DD to AA is also 3030^\circ.
    • In triangle ABDABD, we use the tangent formula: tan(30)=h60\tan(30^\circ) = \frac{h}{60}
    • Solving for hh: h=60×tan(30)=60×13=60×33=20334.64metersh = 60 \times \tan(30^\circ) = 60 \times \frac{1}{\sqrt{3}} = 60 \times \frac{\sqrt{3}}{3} = 20\sqrt{3} \approx 34.64 \, \text{meters}
  3. Using the angle of elevation (60°):

    • For verification, the angle of elevation from DD to AA is 6060^\circ, and using the same approach: tan(60)=h60\tan(60^\circ) = \frac{h}{60}
    • Solving for hh: h=60×360×1.732=103.92metersh = 60 \times \sqrt{3} \approx 60 \times 1.732 = 103.92 \, \text{meters}

Conclusion:

Based on both triangles, the calculations verify the consistency of using the given trigonometric values for height determination.

Would you like a detailed step explanation or have any questions about this problem?

Here are 5 related questions to explore further:

  1. What are the conditions for using the tangent function in right-angled triangles?
  2. How do angles of depression and elevation relate to each other in geometric problems?
  3. Can you solve a similar problem using sine or cosine functions instead?
  4. What role does the distance between two points play in trigonometric calculations?
  5. How would the solution change if the poles had different heights?

Tip: Remember, the tangent of an angle in a right-angled triangle gives the ratio of the opposite side to the adjacent side, which is often useful in height and distance problems.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Right Triangles
Angles of Depression and Elevation

Formulas

tan(θ) = opposite / adjacent

Theorems

Right Triangle Trigonometry

Suitable Grade Level

Grade 10