Math Problem Statement

The second term of a positive magnitude is -6 and the fifth term is 162. (i)

Find the first term of the magnitude and the common ratio.

(ii) The sum of a certain number of terms from the first term of this scale is 1094. Find the number of terms.

Solution

This problem seems to involve a geometric progression (GP), where we are given specific terms and asked to find the first term, the common ratio, and the number of terms that sum to a particular value.

(i) Find the first term and the common ratio

In a geometric progression, each term can be expressed as:

an=arn1a_n = a \cdot r^{n-1}

where:

  • ana_n is the nn-th term,
  • aa is the first term,
  • rr is the common ratio, and
  • nn is the term number.

Given:

  • The second term (a2a_2) is 6-6,
  • The fifth term (a5a_5) is 162162.

We can write the following equations:

a2=ar1=6a_2 = a \cdot r^1 = -6 a5=ar4=162a_5 = a \cdot r^4 = 162

Step 1: Solve for the ratio rr

Divide the second equation by the first to eliminate aa:

ar4ar=1626\frac{a \cdot r^4}{a \cdot r} = \frac{162}{-6}

This simplifies to:

r3=27r^3 = -27

Taking the cube root of both sides:

r=273=3r = \sqrt[3]{-27} = -3

Step 2: Solve for the first term aa

Using the value of rr in the equation for the second term:

a(3)=6a \cdot (-3) = -6

a=63=2a = \frac{-6}{-3} = 2

So, the first term aa is 2, and the common ratio rr is 3-3.

(ii) Find the number of terms nn for which the sum is 1094

The sum SnS_n of the first nn terms of a geometric series is given by:

S_n = a \cdot \frac{1 - r^n}{1 - r} \quad \text{(for r \neq 1)}

Given Sn=1094S_n = 1094, a=2a = 2, and r=3r = -3, we substitute these into the formula:

1094=21(3)n1(3)1094 = 2 \cdot \frac{1 - (-3)^n}{1 - (-3)}

Simplifying:

1094=21(3)n41094 = 2 \cdot \frac{1 - (-3)^n}{4}

Multiply both sides by 4:

4376=2(1(3)n)4376 = 2 \cdot \left(1 - (-3)^n\right)

Divide by 2:

2188=1(3)n2188 = 1 - (-3)^n

Subtract 1 from both sides:

2187=(3)n2187 = (-3)^n

Now, express 21872187 as a power of 3-3:

2187=372187 = 3^7

Since (3)n=37(-3)^n = 3^7, it follows that:

n=7n = 7

So, the number of terms nn is 7.

Summary of Answers:

  1. First Term aa: 22
  2. Common Ratio rr: 3-3
  3. Number of Terms nn: 77

Would you like a more detailed explanation on any part of this problem?

Here are some related questions you might find useful:

  1. How do you determine the nth term in a geometric progression?
  2. What are the properties of a geometric series when the common ratio is negative?
  3. Can you derive the formula for the sum of the first n terms of a geometric series?
  4. How does changing the common ratio affect the sum of a geometric series?
  5. What happens to the sum if the common ratio rr equals 1?

Tip: Always check if the common ratio is positive or negative as it greatly influences the behavior of the sequence.

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Math Problem Analysis

Mathematical Concepts

Geometric Progression (GP)

Formulas

Formula for nth term in a GP
Formula for sum of first n terms in a GP

Theorems

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Suitable Grade Level

Grades 10-12