Math Problem Statement

Question 16: Solve for x. The image shows three angles with algebraic expressions labeled as 10° - 2x, 3x, and 20° - 2.5x.

Solution

The image shows three angles with algebraic expressions. These angles are labeled as follows:

  • 102x10^\circ - 2x
  • 3x3x
  • 202.5x20^\circ - 2.5x

Since these angles form a straight angle (which sums to 180180^\circ), we can set up the following equation:

(102x)+3x+(202.5x)=180(10^\circ - 2x) + 3x + (20^\circ - 2.5x) = 180^\circ

Now, let's solve for xx:

  1. Combine like terms:

10+20+(2x+3x2.5x)=18010^\circ + 20^\circ + (-2x + 3x - 2.5x) = 180^\circ

This simplifies to:

30+(1.5x)=18030^\circ + (-1.5x) = 180^\circ

  1. Subtract 30° from both sides:

1.5x=150-1.5x = 150^\circ

  1. Divide by -1.5 to isolate xx:

x=1501.5=100x = \frac{150^\circ}{-1.5} = -100^\circ

Thus, x=100x = -100.

Would you like further details on any step?

Here are 5 related questions to deepen your understanding:

  1. What are supplementary angles, and why do these angles add up to 180°?
  2. How do we handle negative angles in geometry?
  3. How would the equation change if the angles formed a right angle instead of a straight angle?
  4. Can you verify the solution by plugging x=100x = -100 back into the original angle expressions?
  5. How does the process of combining like terms work in algebra?

Tip: When solving for xx, always check if the angles sum up to the correct total (e.g., 180° for a straight angle).

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Math Problem Analysis

Mathematical Concepts

Algebra
Geometry

Formulas

Sum of angles on a straight line is 180°

Theorems

Straight Angle Theorem

Suitable Grade Level

Grades 8-10