Math Problem Statement

The hanger has been updated to show we’re dividing each side by 2. Now, rewrite the equation to solve for c. c c 28 4c

2c + 28 − 2c − 2c

2c

28 2 2

=

Solution

It looks like you're working with an equation where you want to solve for cc. Based on the way the equation is written, let's break it down clearly.

Given the equation: 4c=2c+284c = 2c + 28

Step 1: To isolate cc, subtract 2c2c from both sides of the equation: 4c2c=284c - 2c = 28

Step 2: Simplify the left side: 2c=282c = 28

Step 3: Now, divide both sides by 2 to solve for cc: c=282c = \frac{28}{2}

c=14c = 14

So, the solution is c=14c = 14.

Would you like further details on this process, or do you have any questions?

Here are some related questions to explore:

  1. What happens if we had a negative term in the equation?
  2. How can we solve equations with fractions or decimals in them?
  3. What would be the solution if we had 5c=3c+425c = 3c + 42?
  4. How do we check if our solution c=14c = 14 is correct by substitution?
  5. What is the effect of multiplying or dividing by negative numbers when solving equations?

Tip: When isolating a variable, remember that any operation you perform on one side must also be performed on the other side to keep the equation balanced.

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations

Formulas

4c = 2c + 28
Solving for c

Theorems

Isolating a variable

Suitable Grade Level

Grades 7-9