We are solving the equation:

$12c - 4 = 14c - 10$

Step 1: Rearrange the equation to group terms with $c$ on one side.

Subtract $12c$ from both sides:

$-4 = 2c - 10$

Step 2: Simplify the constant terms.

Add $10$ to both sides:

$6 = 2c$

Step 3: Solve for $c$.

Divide both sides by $2$:

$c = 3$

Final Answer:

$c = 3$

Would you like further clarification or additional examples?

Here are 5 related questions to explore further:

1. What is the value of $c$ in $5c + 7 = 2c + 19$?
2. How do you solve $8c - 3 = 4c + 9$?
3. Can you explain the steps to check if a solution is correct for a given equation?
4. What happens if the variable $c$ cancels out when solving an equation?
5. How do you solve for $x$ in equations involving fractions, such as $\frac{3x}{2} - 5 = \frac{5x}{4} + 1$?

Tip: Always double-check your solution by substituting it back into the original equation!