To solve for \( b \) in the equation \( A = \frac{1}{2}bh \), follow these steps:

### Given equation:
\[
A = \frac{1}{2}bh
\]

### Step 1: Multiply both sides of the equation by 2 to eliminate the fraction:
\[
2A = bh
\]

### Step 2: Divide both sides by \( h \) to solve for \( b \):
\[
b = \frac{2A}{h}
\]

Thus, the solution is:
\[
b = \frac{2A}{h}
\]

Would you like further details or have any questions?

Here are 5 related questions to explore:
1. How do you find \( h \) if you know \( A \) and \( b \)?
2. What is the formula for the area of a triangle, and how does it relate to this equation?
3. How does this equation change if the base is not perpendicular to the height?
4. What is the geometric interpretation of the equation \( A = \frac{1}{2}bh \)?
5. Can you apply this equation to find the area of any polygon?

**Tip:** When solving for a variable, aim to isolate it by performing inverse operations (like multiplication and division).

Learn how to solve for the base (b) in the triangle area formula A = 1/2bh. This step-by-step solution breaks down the algebraic manipulation required to isolate b, covering key geometric concepts. Suitable for students in Grades 6-8.

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