To solve the formula \( A = \frac{1}{2}bh \) for \( b \), follow these steps:

1. Start with the original formula:
   \[
   A = \frac{1}{2}bh
   \]

2. To isolate \( b \), first multiply both sides of the equation by 2 to eliminate the fraction:
   \[
   2A = bh
   \]

3. Finally, divide both sides by \( h \) to solve for \( b \):
   \[
   b = \frac{2A}{h}
   \]

So, the formula for \( b \) is:
\[
b = \frac{2A}{h}
\]

Would you like more details on any step or have any questions?

Here are 5 related questions for practice:
1. If \( A = 20 \) and \( h = 5 \), what is \( b \)?
2. How would you rearrange the formula to solve for \( h \) instead of \( b \)?
3. What is the geometric meaning of the formula \( A = \frac{1}{2}bh \)?
4. If \( b \) is doubled and \( h \) is halved, how does the area \( A \) change?
5. How can you verify the correctness of the formula \( b = \frac{2A}{h} \) by substituting back into the original equation?

**Tip:** When rearranging formulas, always perform the same operation on both sides of the equation to maintain equality.

Discover how to solve the formula A=1/2bh for b with a detailed step-by-step guide. This problem involves algebraic manipulation and the area of a triangle formula. Suitable for students in Grades 7-9.

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