https://file.aiquickdraw.com/mathbot/file/1730559164774jobnq0qg.jpg

To solve for \( B \), let’s start by substituting \( A = 4 \) in the equation.

The equation given is:
\[
A + B = 0
\]

### Step-by-Step Solution:
1. Substitute \( A = 4 \) into the equation:
   \[
   4 + B = 0
   \]

2. To isolate \( B \), subtract 4 from both sides:
   \[
   B = -4
   \]

### Answer:
So, \( B = -4 \).

Let me know if you'd like more details or have any questions about this problem!

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Here are 5 questions to expand on this problem:

1. How would the solution change if \( A = -4 \)?
2. What would happen if the equation was \( A - B = 0 \) instead?
3. How do you solve for \( B \) if the equation had a different constant instead of 0, like \( A + B = 10 \)?
4. What if the values of \( A \) and \( B \) were variables instead of constants?
5. Can you graph this equation to see where \( B \) intersects when \( A = 4 \)?

**Tip:** Always remember to perform the same operation on both sides of an equation to keep it balanced.

Substitute 4 for A in Equation (1), and solve for B.

Learn how to solve for B in the equation A + B = 0 by substituting A with 4. This basic algebra problem demonstrates simple equation-solving techniques suitable for Grades 6-8.

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