Math Problem Statement

Solve the following differential equation with given initial condition. y prime equals 11 ty minus 12 t​, y left parenthesis 0 right parenthesis equals 1 Question content area bottom Part 1 yequals    enter your response here

Solution

We are given the first-order linear differential equation:

dydt=11ty12t\frac{dy}{dt} = 11ty - 12t

with the initial condition y(0)=1y(0) = 1.

Step 1: Rearrange the equation

We start by writing the differential equation in the form: dydt11ty=12t\frac{dy}{dt} - 11ty = -12t

This is a first-order linear differential equation, and we can solve it using an integrating factor.

Step 2: Find the integrating factor

The integrating factor μ(t)\mu(t) is given by:

μ(t)=e11tdt=e11t2/2\mu(t) = e^{\int -11t dt} = e^{-11t^2/2}

Step 3: Multiply the equation by the integrating factor

Now, multiply the entire differential equation by the integrating factor μ(t)=e11t2/2\mu(t) = e^{-11t^2/2}:

e11t2/2dydt11te11t2/2y=12te11t2/2e^{-11t^2/2} \frac{dy}{dt} - 11t e^{-11t^2/2} y = -12t e^{-11t^2/2}

The left-hand side is the derivative of e11t2/2ye^{-11t^2/2} y, so we can rewrite the equation as:

ddt(e11t2/2y)=12te11t2/2\frac{d}{dt} \left( e^{-11t^2/2} y \right) = -12t e^{-11t^2/2}

Step 4: Integrate both sides

Now, integrate both sides with respect to tt:

e11t2/2y=12te11t2/2dte^{-11t^2/2} y = \int -12t e^{-11t^2/2} dt

The integral on the right-hand side can be computed by recognizing it as a standard form:

12te11t2/2dt=e11t2/2+C\int -12t e^{-11t^2/2} dt = e^{-11t^2/2} + C

Step 5: Solve for y(t)y(t)

Now, solve for y(t)y(t) by dividing both sides by e11t2/2e^{-11t^2/2}:

y(t)=1+Ce11t2/2y(t) = 1 + C e^{11t^2/2}

Step 6: Use the initial condition

We use the initial condition y(0)=1y(0) = 1 to find CC:

1=1+Ce01 = 1 + C e^0

So, C=0C = 0.

Final solution:

Thus, the solution to the differential equation is:

y(t)=1y(t) = 1

Would you like more details on any of these steps?


Here are 5 related questions:

  1. What are the general steps for solving first-order linear differential equations?
  2. How do you compute the integrating factor for a first-order linear differential equation?
  3. Why is the integrating factor method effective for solving differential equations?
  4. Can you solve non-linear first-order differential equations with similar methods?
  5. How do initial conditions help in finding the specific solution to a differential equation?

Tip: Always check your solution by substituting it back into the original differential equation to verify its correctness.

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Math Problem Analysis

Mathematical Concepts

Differential Equations
First-order Linear Differential Equations
Integrating Factor Method

Formulas

dy/dt = 11ty - 12t
Integrating Factor: μ(t) = e^(∫-11t dt) = e^(-11t^2/2)
General Solution: y(t) = 1 + C e^(11t^2/2)

Theorems

First-order Linear Differential Equation Solving Technique
Method of Integrating Factors

Suitable Grade Level

Undergraduate - Calculus I/II