The given expression is:

\[
10 \times ( -2 - (-7)) + 2
\]

Let's break it down:

1. Inside the parentheses, we have \(-2 - (-7)\). Subtracting a negative number is the same as adding the positive equivalent, so:

\[
-2 - (-7) = -2 + 7 = 5
\]

2. Now substitute back into the expression:

\[
10 \times 5 + 2
\]

3. Multiply 10 by 5:

\[
50 + 2
\]

4. Finally, add 2:

\[
50 + 2 = 52
\]

So, the final result is:

\[
\boxed{52}
\]

Would you like any further details or explanations?

Here are 5 related questions:
1. What happens if we subtract two negative numbers in different orders?
2. How do parentheses change the order of operations in math expressions?
3. Can you explain the distributive property in arithmetic?
4. What is the difference between multiplying a positive and a negative number?
5. How do we handle double negatives in subtraction?

**Tip**: Always remember that subtracting a negative is the same as adding the positive equivalent!

Understand how to solve the expression 10×( -2 - (-7)) + 2 using basic arithmetic concepts like subtraction of negative numbers and the order of operations. This step-by-step solution is perfect for students in Grades 6-8, covering essential rules for handling double negatives.

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