Math Problem Statement

2^2x+3^2x=4

Solution

The given equation is:

22x+32x=42^{2x} + 3^{2x} = 4

Let's solve this step by step.

Step 1: Substitute y=2xy = 2^x

We start by substituting y=2xy = 2^x. Therefore, 22x=(2x)2=y22^{2x} = (2^x)^2 = y^2. Now, let's handle 32x3^{2x}.

Step 2: Express 32x3^{2x} in terms of yy

Now, 32x3^{2x} is a bit more complicated. We can leave it as it is but remember that it's independent of yy. The equation becomes:

y2+32x=4y^2 + 3^{2x} = 4

Step 3: Solve using possible scenarios

We try specific values of xx:

Scenario 1: x=0x = 0

22(0)+32(0)=1+1=22^{2(0)} + 3^{2(0)} = 1 + 1 = 2 Does not work.

Scenario 2: x=1x = 1

Then check if x=2x=2:

Generalize by seeking Solution which may include logs:

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Exponential Functions
Equations

Formulas

Exponential function properties

Theorems

-

Suitable Grade Level

Grades 10-12