Math Problem Statement

Suppose that a radioactive substance decays according to M(t) = 2.5e^(-0.002t), where t is time in years. How long will it take for the substance to reach certain percentages of its original amount?

Solution

The image you've uploaded appears to be a screenshot of a document containing mathematical questions about radioactive decay, using the decay function M(t)=M0×2.50.002tM(t) = M_0 \times 2.5^{-0.002t}, where tt is time in years.

The problems address:

  1. Time taken for the substance to decay to 45% and 44% of its original amount and the difference between these times.
  2. Time taken for the substance to decay to 10% of its original amount.

Solution Approach for Part (a) and (b):

  • Use the decay formula to set up an equation based on the percentage remaining (either 45% or 10%) and solve for tt.
  • For (c), the difference in times for the substance to decay from 45% to 44% is sought.

Answer Verification and Explanation:

  1. For 45% Remaining: 0.45=2.50.002t0.45 = 2.5^{-0.002t} Taking the natural logarithm: ln(0.45)=0.002tln(2.5)\ln(0.45) = -0.002t \ln(2.5) Solving for tt: t=ln(0.45)0.002ln(2.5)t = \frac{\ln(0.45)}{-0.002 \ln(2.5)}

  2. For 10% Remaining: 0.10=2.50.002t0.10 = 2.5^{-0.002t} Similarly, taking the natural logarithm and solving for tt: t=ln(0.10)0.002ln(2.5)t = \frac{\ln(0.10)}{-0.002 \ln(2.5)}

Part (c):

  • The reason the answers for (a) and (b) are not the same is that the percentage decay is not linear over time. The exponential decay function models the process whereby the amount of substance decreases rapidly at first and then more slowly as time progresses.

Let's calculate the exact values for the times in years for each decay percentage and check the given solutions:

  1. Time for the substance to decay to 45%.
  2. Time for the substance to decay to 44%.
  3. Time for the substance to decay to 10%.
  4. Verify why the time differences for small percentage changes are significant as the substance approaches complete decay.

Let me perform the calculations.Here are the computed results based on the exponential decay model M(t)=M0×2.50.002tM(t) = M_0 \times 2.5^{-0.002t}:

  1. Time to decay to 45% of original amount: Approximately 435.73 years.
  2. Time to decay to 44% of original amount: Approximately 447.99 years.
  3. Time to decay to 10% of original amount: Approximately 1256.47 years.

Time Differences:

  • From 45% to 44%: The time difference is about 12.26 years.
  • From 45% to 10%: The time difference is about 820.74 years.

Explanation:

  • The difference in time for the substance to decay from 45% to 44% (12.26 years) shows how sensitive the decay process is to small percentage changes

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Math Problem Analysis

Mathematical Concepts

Exponential Decay
Logarithms
Differential Equations

Formulas

Exponential Decay: M(t) = M_0 e^{-kt}
Logarithmic transformation: ln(A) = k * t

Theorems

Natural Logarithms and Exponentials
Exponential Growth and Decay Theorem

Suitable Grade Level

Grade 12 - University Level