Math Problem Statement

21+@DIV{2;3}t=50-@DIV{11;12}t

Solution

Let's solve the equation step by step. The given equation is:

21+23t=501112t21 + \frac{2}{3}t = 50 - \frac{11}{12}t

Step 1: Eliminate the fractions by finding a common denominator.

The common denominator for 23\frac{2}{3} and 1112\frac{11}{12} is 12. Multiply the entire equation by 12 to eliminate the fractions:

12×21+12×23t=12×5012×1112t12 \times 21 + 12 \times \frac{2}{3}t = 12 \times 50 - 12 \times \frac{11}{12}t

This simplifies to:

252+8t=60011t252 + 8t = 600 - 11t

Step 2: Move the terms involving tt to one side and constants to the other.

Add 11t11t to both sides:

252+8t+11t=600252 + 8t + 11t = 600

This simplifies to:

252+19t=600252 + 19t = 600

Step 3: Isolate the variable tt.

Subtract 252 from both sides:

19t=34819t = 348

Finally, divide by 19:

t=34819=18.32t = \frac{348}{19} = 18.32

Final Answer:

t=18.32t = 18.32

Would you like further details or have any questions?

Here are some related questions:

  1. How do you solve linear equations with fractions?
  2. What are the steps to isolate a variable in an equation?
  3. How can you check if your solution to an equation is correct?
  4. What methods can be used to simplify fractions in equations?
  5. What are common mistakes when solving equations with fractions?

Tip: Always simplify fractions as early as possible to make calculations easier.

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Math Problem Analysis

Mathematical Concepts

Algebra
Equations
Fractions

Formulas

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Theorems

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Suitable Grade Level

Grades 9-12