Math Problem Statement

a2\sqrt{a-2}=2b+1\sqrt{b+1} equation 1 3(c4)3^{\left(c-4\right)}+1=abab equation 2 \log_{b}\left(d\right) $$$$ -1=\log_{b}\left(d-16\right) equation 3 log(a4)\log\left(a-4\right)=1 equation 4 aad ⁣bdt\int_{aa}^{d}\!b\,\mathrm{dt-}m.c.m(abcd)abcd)=? what will be the answer ? is there any possibility that answer would be from this options (32,16,2,240,224,14)

Solution

Let's solve the system of equations step by step to find the correct answer.

Step 1: Solve Equation 4

Given: log(a4)=1\log(a - 4) = 1 This can be rewritten as: a4=101=10a - 4 = 10^1 = 10 a=14(Equation 4.1)a = 14 \quad \text{(Equation 4.1)}

Step 2: Substitute a=14a = 14 into Equation 1

Given: a2=2b+1\sqrt{a - 2} = 2\sqrt{b + 1} Substitute a=14a = 14: 142=2b+1\sqrt{14 - 2} = 2\sqrt{b + 1} 12=2b+1\sqrt{12} = 2\sqrt{b + 1} Square both sides: 12=4(b+1)12 = 4(b + 1) 12=4b+412 = 4b + 4 4b=84b = 8 b=2(Equation 1.1)b = 2 \quad \text{(Equation 1.1)}

Step 3: Substitute a=14a = 14 and b=2b = 2 into Equation 2

Given: 3c4+1=ab3^{c-4} + 1 = ab Substitute a=14a = 14 and b=2b = 2: 3c4+1=14×23^{c-4} + 1 = 14 \times 2 3c4+1=283^{c-4} + 1 = 28 Subtract 1 from both sides: 3c4=273^{c-4} = 27 Since 27=3327 = 3^3, we get: c4=3c - 4 = 3 c=7(Equation 2.1)c = 7 \quad \text{(Equation 2.1)}

Step 4: Substitute b=2b = 2 into Equation 3

Given: logb(d)1=logb(d16)\log_b(d) - 1 = \log_b(d - 16) Add 1 to both sides: logb(d)=logb(d16)+1\log_b(d) = \log_b(d - 16) + 1 Convert this logarithmic equation into its exponential form: d=b(d16)d = b \cdot (d - 16) Substitute b=2b = 2: d=2(d16)d = 2(d - 16) d=2d32d = 2d - 32 d2d=32d - 2d = -32 d=32-d = -32 d=32(Equation 3.1)d = 32 \quad \text{(Equation 3.1)}

Step 5: Evaluate the Given Expression

We need to compute: adbdtm.c.m(abcd)\int_{a}^{d} b \, dt - \text{m.c.m}(ab \cdot c \cdot d)

Compute the Integral

14322dt=2×(3214)=2×18=36\int_{14}^{32} 2 \, dt = 2 \times (32 - 14) = 2 \times 18 = 36

Compute the m.c.m (LCM) of abcdab \cdot c \cdot d

The product abcdab \cdot c \cdot d is: abcd=14×2×7×32=6272ab \cdot c \cdot d = 14 \times 2 \times 7 \times 32 = 6272 The least common multiple (LCM) of 62726272 is 62726272 itself.

Final Calculation

adbdtm.c.m(abcd)=366272=6236\int_{a}^{d} b \, dt - \text{m.c.m}(ab \cdot c \cdot d) = 36 - 6272 = -6236

Conclusion

The final answer, 6236-6236, does not match any of the provided options (32, 16, 2, 240, 224, 14). Therefore, the correct answer is not among the options given.

Would you like more details or have any further questions?

Related Questions:

  1. How do you determine the LCM of a set of numbers?
  2. What is the significance of solving logarithmic equations?
  3. Why is squaring both sides of an equation sometimes necessary?
  4. How does the definite integral apply to calculating areas?
  5. What are some common mistakes when solving systems of equations?

Tip: Always verify each step carefully to ensure there are no calculation errors, especially when working with logarithms and exponents.

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Math Problem Analysis

Mathematical Concepts

Logarithms
Exponential Equations
Definite Integral

Formulas

Logarithm properties
Exponential equations

Theorems

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Suitable Grade Level

Advanced High School