You have the equation:

$(x - 3)^2 = 5$

To solve for $x$, follow these steps:

1. Take the square root of both sides to eliminate the square: $\sqrt{(x - 3)^2} = \pm \sqrt{5}$ Which simplifies to: $x - 3 = \pm \sqrt{5}$

2. Solve for $x$ by adding 3 to both sides: $x = 3 \pm \sqrt{5}$

Thus, the two solutions for $x$ are: $x = 3 + \sqrt{5} \quad \text{or} \quad x = 3 - \sqrt{5}$

If you want a decimal approximation: $x \approx 3 + 2.236 \quad \text{or} \quad x \approx 3 - 2.236$ So: $x \approx 5.236 \quad \text{or} \quad x \approx 0.764$

Would you like more details or have any questions about the process?

Here are 5 related questions:

1. What is the method to solve quadratic equations in general?
2. How do you handle negative numbers under square roots?
3. Can complex numbers be a solution to this equation?
4. How can you graph the function $(x-3)^2 - 5 = 0$?
5. What does it mean to "complete the square" in algebra?

Tip: Always remember, taking the square root of both sides introduces both the positive and negative roots!