Math Problem Statement

y' = 2y y(x) = C * e ^ (2x) y(0) = 3

Solution

The plot above shows several solutions to the differential equation y=2yy' = 2y with different values of CC. The red dashed line represents the specific solution y(x)=3e2xy(x) = 3e^{2x} that satisfies the initial condition y(0)=3y(0) = 3. Each curve represents different exponential growth or decay based on the constant CC.

Would you like more details or have any questions?

Here are some related questions to explore:

  1. What is the general behavior of solutions to the differential equation y=kyy' = ky for different values of kk?
  2. How does changing the initial condition y(0)=y0y(0) = y_0 affect the solution?
  3. What is the significance of the constant CC in the general solution y(x)=Ce2xy(x) = Ce^{2x}?
  4. How would you solve a differential equation of the form y=ay+by' = ay + b?
  5. Can the differential equation y=2yy' = 2y be solved using separation of variables? How?

Tip: For differential equations of the form y=kyy' = ky, solutions will exhibit exponential growth or decay depending on the sign of kk.

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Math Problem Analysis

Mathematical Concepts

Differential Equations
Exponential Growth and Decay

Formulas

General solution of y' = ky: y(x) = Ce^(kx)
Initial condition: y(0) = y0

Theorems

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Suitable Grade Level

Grades 11-12