Math Problem Statement

Solve the differential equation x (dy/dx) + (1 + x)y = x^3

Solution

The given equation is:

xdydx+(1+x)y=x3x \frac{dy}{dx} + (1 + x)y = x^3

This is a first-order linear differential equation, which can be solved using the integrating factor method.


Step 1: Rewrite the equation in standard form

dydx+(1+x)xy=x2\frac{dy}{dx} + \frac{(1 + x)}{x}y = x^2

Here:

  • P(x)=1+xxP(x) = \frac{1 + x}{x},
  • Q(x)=x2Q(x) = x^2.

Step 2: Compute the integrating factor

The integrating factor I(x)I(x) is given by: I(x)=eP(x)dx=e1+xxdxI(x) = e^{\int P(x) \, dx} = e^{\int \frac{1 + x}{x} \, dx}

Break the integral: 1+xxdx=1xdx+1dx=lnx+x\int \frac{1 + x}{x} \, dx = \int \frac{1}{x} \, dx + \int 1 \, dx = \ln|x| + x

Thus: I(x)=elnx+x=elnxex=xexI(x) = e^{\ln|x| + x} = e^{\ln|x|} \cdot e^x = x e^x


Step 3: Multiply through by the integrating factor

Multiply the entire equation by I(x)=xexI(x) = x e^x: xexdydx+xex1+xxy=x3exx e^x \frac{dy}{dx} + x e^x \cdot \frac{1 + x}{x} y = x^3 e^x

Simplify: xexdydx+(1+x)exy=x3exx e^x \frac{dy}{dx} + (1 + x)e^x y = x^3 e^x

Notice the left-hand side is the derivative of (exxy)(e^x x y): ddx(exxy)=x3ex\frac{d}{dx} (e^x x y) = x^3 e^x


Step 4: Integrate both sides

Integrate with respect to xx: exxy=x3exdxe^x x y = \int x^3 e^x \, dx

To integrate x3exdx\int x^3 e^x \, dx, use integration by parts repeatedly. Let:

  • u=x3u = x^3, dv=exdxdv = e^x dx,
  • du=3x2dxdu = 3x^2 dx, v=exv = e^x.

Using the formula udv=uvvdu\int u \, dv = uv - \int v \, du: x3exdx=x3ex3x2exdx\int x^3 e^x \, dx = x^3 e^x - \int 3x^2 e^x \, dx

Repeat this process for x2exdx\int x^2 e^x dx and xexdx\int x e^x dx. After completing all steps, the result is: x3exdx=ex(x33x2+6x6)\int x^3 e^x \, dx = e^x (x^3 - 3x^2 + 6x - 6)

Thus: exxy=ex(x33x2+6x6)+Ce^x x y = e^x (x^3 - 3x^2 + 6x - 6) + C


Step 5: Solve for yy

Divide through by exxe^x x: y=x33x2+6x6x+Cxexy = \frac{x^3 - 3x^2 + 6x - 6}{x} + \frac{C}{x e^x}

Simplify: y=x23x+66x+Cxexy = x^2 - 3x + 6 - \frac{6}{x} + \frac{C}{x e^x}


Final Solution:

y=x23x+66x+Cxexy = x^2 - 3x + 6 - \frac{6}{x} + \frac{C}{x e^x}

Let me know if you'd like detailed steps on any part of the process!


Questions:

  1. What is the significance of an integrating factor in solving linear differential equations?
  2. How do you calculate an integrating factor for first-order equations?
  3. What are the steps to simplify after finding the integrating factor?
  4. Why do we use integration by parts for certain terms during integration?
  5. How does the constant of integration CC affect the final solution?

Tip: Always rewrite differential equations in their standard form before applying solution methods like the

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Math Problem Analysis

Mathematical Concepts

First-Order Linear Differential Equations
Integrating Factor Method
Integration by Parts

Formulas

Integrating Factor: I(x) = e^(∫P(x) dx)
General Solution for Linear Differential Equation: e^x * y = ∫x^3 e^x dx
Integration by Parts: ∫ u dv = uv - ∫ v du

Theorems

Linearity of Differential Equations
Method of Integrating Factors
Integration by Parts

Suitable Grade Level

Grades 11-12