Math Problem Statement

Giải hệ phương trình: {x^3 + z^3 = 3y y^3 + x^3 = 3z z^3 + y^3 = 3x} Cho hai số nguyên dương a, b phân biệt. Chứng minh phương trình sau có đúng ba nghiệm: (\sqrt{x-1})[x^2 - 2(a+b)x + ab + 2] = 0.

Solution

I see you've uploaded a math problem written in Vietnamese. Here’s a breakdown of the two tasks provided:

  1. Solving the system of equations: x^3 + z^3 = 3y \\ y^3 + x^3 = 3z \\ z^3 + y^3 = 3x \end{cases}$$ The goal here is to find the values of $$x$$, $$y$$, and $$z$$ that satisfy this system.
  2. Proving the equation has three solutions for two distinct integer values aa and bb: (x1)[x22(a+b)x+ab+2]=0\left( \sqrt{x-1} \right) \left[ x^2 - 2(a+b)x + ab + 2 \right] = 0 This is the second part of the problem where we need to show that the equation has exactly three solutions.

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Math Problem Analysis

Mathematical Concepts

System of Equations
Algebra
Roots of Equations
Proof by Contradiction

Formulas

x^3 + z^3 = 3y
y^3 + x^3 = 3z
z^3 + y^3 = 3x
(\sqrt{x-1})[x^2 - 2(a+b)x + ab + 2] = 0

Theorems

Vieta's Formulas
Fundamental Theorem of Algebra

Suitable Grade Level

Grades 10-12